| Weighted Matroid |
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| CATEGORIES ABOUT WEIGHTED MATROID | |
| matroid theory | |
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In Combinatorics , a branch of Mathematics , a weighted matroid is a Matroid endowed with function with respect to which one can perform a greedy algorithm. There is a simple algorithm for finding a basis:
The result is clearly an independent set. It is a maximal independent set because if B U {x} is not independent for some subset B of A, then A U {x} is not independent either (the contrapositive follows from the hereditary property). Thus if we pass up an element, we'll never have an opportunity to use it later. We will generalize this algorithm to solve a harder problem. A ''weight function'' ''w'' : ''E'' → R+ for a matroid ''M''=(''E'', ''I'') assigns a strictly positive weight to each element of ''E''. We extend the function to subsets of ''E'' by summation; ''w''(''A'') is the sum of ''w''(''x'') over ''x'' in ''A''. A matroid with an associated weight function is called a weighted matroid. As a simple example, say we wish to find the Maximum Spanning Forest of a graph. That is, given a graph and a weight for each edge, find a forest containing every vertex and maximizing the total weight of the edges in the tree. This problem arises in some clustering applications. If we look at the definition of the forest matroid above, we see that the maximum spanning forest is simply the independent set with largest total weight — such a set must span the graph, for otherwise we can add edges without creating cycles. But how do we find it? An independent set of largest total weight is called an ''optimal'' set. Optimal sets are always bases, because if an edge can be added, it should be; this only increases the total weight. As it turns out, there is a trivial Greedy Algorithm for computing an optimal set of a weighted matroid. It works as follows:
This algorithm finds a basis, since it is a special case of the above algorithm. It always chooses the element of largest weight that it can while preserving independence (thus the term "greedy"). This always produces an optimal set: suppose that it produces and that . Now for any with , consider open sets and . Since is smaller than , there is some element of which can be put into with the result still being independent. However is an element of maximal weight that can be added to to maintain independence. Thus is of no smaller weight than some element of , and hence is of at least a large a weight as . As this is true for all , is weightier than . |
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