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There are two types of dual spaces: the algebraic dual space, and the continuous dual space. The algebraic dual space is defined for all vector spaces. When defined for a Topological Vector Space there is a subspace of this dual space, corresponding to continuous linear functionals, which constitutes a ''continuous dual space''. ALGEBRAIC DUAL SPACE
: : The finite dimensional case
: In the case of R2, its basis is ''B''={'''e'''1=(1,0),'''e'''2=(0,1)}. Then, '''e'''1, and '''e'''2 are one-forms (functions which map a vector to a scalar) such that '''e'''1('''e'''1)=1, '''e'''1('''e'''2)=0, '''e'''2('''e'''1)=0, and '''e'''2('''e'''2)=1. (Note: The superscript here is an index, not an exponent.) Concretely, if we interpret R''n'' as the space of columns of ''n'' Real Number s, its dual space is typically written as the space of ''rows'' of ''n'' real numbers. Such a row acts on R''n'' as a linear functional by ordinary Matrix Multiplication .
The infinite dimensional case If ''V'' is not finite-dimensional but has a basisSeveral assertions in this article require the elements e''α'' (''α''∈''A'') of the dual space, but they will not form a basis. Consider, for instance, the space R∞, whose elements are those of R∞ is countably infinite, whereas R'''N''' does not have a countable basis. This observation generalizes to any infinite dimensional vector space ''V'' over any field F: a choice of basis {'''e'''''α'':''α''∈''A''} identifies ''V'' with the space (F''A'')0 of functions ''f'':''A''→F such that ''f''''α''=''f''(''α'') is nonzero for only finitely many ''α''∈''A'', where such a function ''f'' is identified with the vector : in ''V'' (the sum is finite by the assumption on ''f'' and any ''v''∈''V'' may be written in this way by the definition of a basis). The dual space of ''V'' may then be identified with the space F''A'' of ''all'' functions from ''A'' to F: a linear functional ''T'' on ''V'' is uniquely determined by the values ''θ''''α''=''T''('''e'''''α'') it takes on the basis of ''V'', and any function ''θ'':''A''→F (with ''θ''(''α'')=''θ''''α'') defines linear functional ''T'' on ''V'' by : Again the sum is finite because ''f''''α'' is nonzero for only finitely many ''α''. Note that (F''A'')0 may be identified (essentially by definition) with the Direct Sum of infinitely many copies of F (viewed as a 1-dimensional vector space over itself) indexed by ''A'', i.e., there are linear isomorphisms : On the other hand F''A'' is (again by definition), the Direct Product of infinitely many copies of F indexed by ''A'', and so the identification
is a special case of a General Result relating direct sums (of modules) to direct products. Thus if the basis is infinite, then there are ''always'' more vectors in the dual space than the original vector space. This is in marked contrast to the case of the continuous dual space, discussed below, which may be isomorphic to the original vector space even if the latter is infinite-dimensional. Bilinear products and dual spaces
:
Injection into the double-dual
Transpose of a linear map
CONTINUOUS DUAL SPACE ''See main article Continuous Dual Space ''
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|   | In Analogy With The Case Of The Algebraic Double Dual, There Is Always A Naturally Defined Injective Continuous Linear Operator &Psi&nbsp:&nbsp''V'' &rarr ''V'' &prime&prime From ''V'' Into Its Continuous Double Dual ''V'' &prime&prime This Map Is In Fact An | "http://wwwinformationdelightinfo/information/entry/isometry" class="copylinks">Isometry , meaning &Psi(''x'') = ''x'' for all ''x'' in ''V'' Spaces for which the map &Psi is a Bijection are called Reflexive |
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