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CONSTRUCTION The Total Space of the Universal Bundle is given by : Here, ''H'' is an infinite-dimensional complex Hilbert space, the are vectors in ''H'', and is the Kronecker Delta . The symbol is the Inner Product on ''H''. Thus, we have that ''EU(n)'' is the space of Orthonormal ''n''-frames in ''H''. The Group Action of ''U''(''n'') on this space is the natural one. The Base Space is then : and is the set of Grassmannian ''n''-dimensional subspaces (or ''n''-planes) in ''H''. That is, : so that ''V'' is an ''n''-dimensional vector space. VALIDITY OF THE CONSTRUCTION In this section, we will define the topology on ''EU(n)'' and prove that ''EU(n)'' is indeed contractible. Let be the space of orthonormal families of vectors in . The group acts freely on and the quotient is the Grassmannian of -dimensional subvector spaces of . The map : is a fibre bundle of fibre . Thus because is trivial and because of the Long Exact Sequence Of The Fibration , we have : whenever . By taking big enough, precisely for , we can repeat the process and get : This last group is trivial for . Let : be the Direct Limit of all the (with the induced topology). Let : be the Direct Limit of all the (with the induced topology). Lemma The group is trivial for all . Proof Let be a map from the sphere to ''EU(n)''. As is Compact , there exists such that is included in . By taking big enough, we see that is homotopic, with respect to the base point, to the constant map. In addition, acts freely on ''EU(n)''. The spaces and are CW-complexes . One can find a decomposition of these spaces into CW-complexes such that the decomposition of , resp. , is induced by restriction of the one for , resp. . Thus ''EU(n)'' (and also ) is a CW-complexe. By Whitehead Theorem and the above Lemma, ''EU''(''n'') is contractible. CASE OF ''N'' = 1 In the case of ''n'' = 1, one has : Taking the quotient of by an action of , the group of positive numbers by multiplication (this does not change the homotopy type of the space, being isomorphic to ), one sees that the space is essentially a unit ball in a complex countable-dimension vector space. The base space is then : the infinite-dimensional Complex Projective Space . Thus, the set of Isomorphism Class es of Circle Bundle s over a Manifold ''M'' are in one-to-one correspondence with the Homotopy Class es of maps from ''M'' to . One also has the relation that : that is, BU(1) is the infinite-dimensional Projective Unitary Group . See that article for additional discussion and properties. COHOMOLOGY OF THE CLASSIFYING SPACE BU(N) Proposition
where is of degree ''2p''. Proof Let us first consider the case ''n=1''. In this case, ''U(1)'' is the circle and the universal bundle is . It is well knownR. Bott, L. W. Tu -- ''Differential Forms in Algebraic Topology'', Graduate Texts in Mathematics 82, Springer that the cohomology of is isomorphic to , where is the Euler Class of the ''U(1)''-bundle , and that the injections ,
This proves the Proposition for ''n=1''. In the general case, let ''T'' be the subgroup of diagonal matrices. It is a Maximal Torus in ''U(n)''. Its classifying space is and its cohomology is , where is the `Euler class' of the tautological bundle over the ''i''-th . The Weyl Group acts on by permuting the diagonal entries, hence it acts on by permutation of the factors. The induce action on its cohomology is the permutation of the 's. We deduce
where the 's are the Symmetric Polynomials in the 's. SEE ALSO REFERENCES |
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