Classifying Space For U(n) Article Index for
Classifying Space
Website Links For
Space
 

Information About

Classifying Space For U(n)





CONSTRUCTION

The Total Space EU(n) of the Universal Bundle is given by

:EU(n)=\{e_1,\ldots,e_n : (e_i,e_j)=\delta_{ij}, e_i\in \mathcal{H} \}.

Here, ''H'' is an infinite-dimensional complex Hilbert space, the e_i are vectors in ''H'', and \delta_{ij} is the Kronecker Delta . The symbol (\cdot,\cdot) is the Inner Product on ''H''. Thus, we have that ''EU(n)'' is the space of Orthonormal ''n''-frames in ''H''.

The Group Action of ''U''(''n'') on this space is the natural one. The Base Space is then

:BU(n)=EU(n)/U(n)

and is the set of Grassmannian ''n''-dimensional subspaces (or ''n''-planes) in ''H''. That is,

:BU(n) = \{ V \subset \mathcal{H} : \dim V = n \}

so that ''V'' is an ''n''-dimensional vector space.


VALIDITY OF THE CONSTRUCTION

In this section, we will define the topology on ''EU(n)'' and prove that ''EU(n)'' is indeed contractible.

Let F_n(\mathbb{C}^k) be the space of orthonormal families of n vectors in \mathbb{C}^k. The group U(n) acts
freely on F_n(\mathbb{C}^k) and the quotient is the Grassmannian G_n(\mathbb{C}^k) of n-dimensional subvector spaces of \mathbb{C}^k. The map

: \begin{align}
F_n(\mathbb{C}^k) & \longrightarrow & S^{2k-1} \
(e_1,\ldots,e_n) & \longmapsto & e_n
\end{align}

is a fibre bundle of fibre F_{n-1}(\mathbb{C}^{k-1}). Thus because \pi_p(S^{2k-1}) is trivial and because of the Long Exact Sequence Of The Fibration , we have

: \pi_p(F_n(\mathbb{C}^k))=\pi_p(F_{n-1}(\mathbb{C}^{k-1}))

whenever p\leq 2k-2. By taking k big enough, precisely for k> rac{1}{2}p+n-1, we can repeat the process and get

: \pi_p(F_n(\mathbb{C}^k)) = \pi_p(F_{n-1}(\mathbb{C}^{k-1})) = \cdots = \pi_p(F_1(\mathbb{C}^{k+1-n})) = \pi_p(S^{k-n}).

This last group is trivial for k>n+p. Let

: EU(n)={\lim_{ ightarrow}}\;_{k ightarrow\infty}F_n(\mathbb{C}^k)

be the Direct Limit of all the F_n(\mathbb{C}^k) (with the induced topology). Let

: G_n(\mathbb{C}^\infty)={\lim_{ ightarrow}}\;_{k ightarrow\infty}G_n(\mathbb{C}^k)

be the Direct Limit of all the G_n(\mathbb{C}^k) (with the induced topology).

Lemma

The group \pi_p(EU(n)) is trivial for all p\ge 1.

Proof
Let \gamma be a map from the sphere S^p to ''EU(n)''. As S^p is Compact ,
there exists k such that \gamma(S^p) is included in F_n(\mathbb{C}^k). By taking k big enough,
we see that \gamma is homotopic, with respect to the base point, to the constant map.
\Box

In addition, U(n) acts freely on ''EU(n)''. The spaces F_n(\mathbb{C}^k) and G_n(\mathbb{C}^k) are CW-complexes . One can
find a decomposition of these spaces into CW-complexes such that the decomposition of F_n(\mathbb{C}^k), resp.
G_n(\mathbb{C}^k), is induced by restriction of the one for F_n(\mathbb{C}^{k+1}), resp. G_n(\mathbb{C}^{k+1}). Thus ''EU(n)'' (and also G_n(\mathbb{C}^\infty)) is a CW-complexe. By
Whitehead Theorem and the above Lemma, ''EU''(''n'') is contractible.


CASE OF ''N'' = 1


In the case of ''n'' = 1, one has

:EU(1)= \mathbb {C}^\infty.\,

Taking the quotient of \mathbb{C}^\infty by an action of \mathbb R^+, the group of positive numbers by multiplication (this does not change the homotopy type of the space, \mathbb R^+ being isomorphic to R), one sees that the space is essentially a unit ball in a complex countable-dimension vector space. The base space is then

:BU(1)= \mathbb{C}P^\infty,\,

the infinite-dimensional Complex Projective Space . Thus, the set of Isomorphism Class es of Circle Bundle s over a Manifold ''M'' are in one-to-one correspondence with the Homotopy Class es of maps from ''M'' to \mathbb{C}P^\infty.

One also has the relation that

:BU(1)= PU(\mathcal{H}),

that is, BU(1) is the infinite-dimensional Projective Unitary Group . See that article for additional discussion and properties.


COHOMOLOGY OF THE CLASSIFYING SPACE BU(N)

Proposition

  • (BU(n)) is a Ring of Polynomials in ''n'' variables

  • c_1,\ldots,c_n where c_p is of degree ''2p''.


Proof
Let us first consider the case ''n=1''. In this case, ''U(1)'' is the circle S^1 and the universal bundle
is S^\infty\longrightarrow CP^\infty. It is well knownR. Bott, L. W. Tu
-- ''Differential Forms in Algebraic Topology'', Graduate Texts in Mathematics 82,
Springer that the cohomology of
CP^k is isomorphic to \mathbb{R}\lbrack c_1 brack/c_1^{k+1}, where c_1 is the Euler Class of
the ''U(1)''-bundle S^{2k+1}\longrightarrow CP^k, and that the injections CP^k\longrightarrow CP^{k+1},
  • , are compatible with these presentations of the cohomology of the projective spaces.

  • This proves the Proposition for ''n=1''.


In the general case, let ''T'' be the subgroup of diagonal matrices. It is a Maximal Torus in ''U(n)''. Its
classifying space is (CP^\infty)^n and its cohomology is \mathbb{R}\lbrack x_1,\ldots,x_n brack, where
x_i is the `Euler class' of the tautological bundle over the ''i''-th CP^\infty. The
Weyl Group acts on T by permuting the diagonal entries, hence it acts on (CP^\infty)^n by
permutation of the factors. The induce action on its cohomology is the permutation of the
x_i's. We deduce
  • (BU(n))=\mathbb{R}\lbrack c_1,\ldots,c_n brack,

  • where the c_i's are the Symmetric Polynomials in the x_i's.

\Box



SEE ALSO



REFERENCES