Table Of Derivatives Article Index for
Table Of
Website Links For
Table
 

Information About

Table Of Derivatives




The primary operation in Differential Calculus is finding a Derivative . This table lists derivatives of many functions. In the following, ''f'' and ''g'' are differentiable functions from the Real Number s, and ''c'' is a real number. These formulas are sufficient to differentiate any Elementary Function .


Rules for differentiation of general functions


;Constant multiple rule
:\left({cf} ight)' = cf'
;Linearity
:\left({f + g} ight)' = f' + g'
:\left({f - g} ight)' = f' - g'
;Product rule
:\left({fg} ight)' = f'g + fg'
;Quotient rule
:\left({f \over g} ight)' = {f'g - fg' \over g^2}, \qquad g
e 0
;Functional power rule
:(f^g)' = \left(e^{g\ln f} ight)' = f^g\left(f'{g \over f} + g'\ln f ight),\qquad f > 0
;Chain rule
:(f \circ g)' = (f' \circ g)g'
;Logarithm rule
:(\ln f)' = rac{f'}{f}, \qquad f
e 0


Derivatives of simple functions


:{d \over dx} c = 0

:{d \over dx} x = 1

:{d \over dx} cx = c




:{d \over dx} \left({1 \over x} ight) = {d \over dx} \left(x^{-1} ight) = {d \over dx} \left(-x^{-2} ight) = -{1 \over x^2}

:{d \over dx} \sqrt{x} = {d \over dx} x^{1\over 2} = {1 \over 2} x^{-{1\over 2}} = {1 \over 2 \sqrt{x}}, \qquad x > 0


Derivatives of Exponential and Logarithmic functions


:{d \over dx} c^x = {c^x \ln c},\qquad c > 0

:{d \over dx} e^x = e^x

:{d \over dx} \log_c x = {1 \over x \ln c},\qquad c > 0, c
e 1

:{d \over dx} \ln x = {1 \over x}


Derivatives of Trigonometric functions


:{d \over dx} \sin x = \cos x

:{d \over dx} \cos x = -\sin x

:{d \over dx} an x = \sec^2 x

:{d \over dx} \sec x = an x \sec x

:{d \over dx} \cot x = -\csc^2 x

:{d \over dx} \csc x = -\csc x \cot x

:{d \over dx} \arcsin x = { 1 \over \sqrt{1 - x^2}}

:{d \over dx} \arccos x = {-1 \over \sqrt{1 - x^2}}

:{d \over dx} \arctan x = { 1 \over 1 + x^2}






:{d \over dx} \mbox{arccosh} x = { 1 \over \sqrt{x^2 - 1}}

:{d \over dx} \mbox{arctanh} x = { 1 \over 1 - x^2}

:{d \over dx} \mbox{arcsech} x = { 1 \over x\sqrt{1 - x^2}}

:{d \over dx} \mbox{arccoth} x = { 1 \over 1 - x^2}