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Specific Impulse




Depending on whether the amount of propellant is expressed in mass or by weight (conventionally sea level weight on the Earth ) the Dimension of specific impulse is that of speed or time, respectively, differing by a factor of '' G '', the gravitational acceleration at the surface of the Earth.


GENERAL CONSIDERATIONS

Essentially, the higher the specific impulse, the less propellant is needed to gain a given amount of momentum. In this regard a propulsion method is more fuel-efficient if the specific impulse is higher. This should not in any way be confused with energy-efficiency, which can even decrease as specific impulse increases, since many propulsion systems that give high specific impulse require high energy to do so.

In addition it is important that Thrust and specific impulse not be confused with one another. The specific impulse is a measure of the ''thrust per unit of propellant'' that is expelled, while
thrust is a measure of the momentary or peak force supplied by a particular engine. In fact, propulsion systems with very high specific impulses (such as Ion Thruster s: 3,000 seconds) are power limited to producing low thrusts, due to the relatively high weight of power generators.

When calculating specific impulse, only propellant that is carried with the vehicle before use is counted. For a chemical rocket the propellant mass therefore would include both fuel and Oxidizer ; for air-breathing engines only the mass of the fuel is counted, not the mass of air passing through the engine.


EXAMPLES


Specific impulse of various propulsion technologies

An example of a specific impulse measured in time is 453 Second s, or, equivalently, an effective exhaust velocity of 4500 M/s , for the Space Shuttle Main Engine s when operating in vacuum.

An air-breathing engine typically has a much larger specific impulse than a rocket: a jet engine may have a specific impulse of 2000-3000 seconds or more at sea level.

In some ways, comparing specific impulse seems unfair in the case of jet engines and rockets. However in rocket or jet powered aircraft, specific impulse is approximately proportional to range, and rockets do indeed perform much worse than jets below approximately 85000 feet (~25 km) in that regard.

The highest specific impulse for a chemical propellant ever test-fired in a rocket engine was lithium, fluorine, and hydrogen (a .

Nuclear Thermal Rocket engines differ from conventional rocket engines in that thrust is created strictly through thermodynamic phenomena, with no chemical reaction. The nuclear rocket typically operates by passing hydrogen gas over a superheated nuclear core. Testing in the 1960s yielded specific impulses of about 850 seconds (8340 m/s), about twice that of the Space Shuttle engines.

A variety of other non-rocket propulsion methods, such as Ion Thruster s, give much higher specific impulse but with much lower thrust; for example the Hall Effect Thruster on the Smart 1 satellite has a specific impulse of 1640 s (16100 m/s) but a maximum thrust of only 68 millinewtons. The hypothetical Variable Specific Impulse Magnetoplasma Rocket (VASIMR) propulsion should yield a minimum of 10,000-300,000 m/s but will probably require a great deal of heavy machinery to confine even relatively diffuse plasmas, so they will be unusable for very-high-thrust applications such as launch from planetary surfaces.

The Nuclear Photonic Rocket represents the theoretical limit: total conversion of matter to energy, all usable as thrust; one possible incarnation of this would be some kind of antimatter-pumped laser device.


SPECIFIC IMPULSE IN SECONDS


For all vehicles specific impulse (impulse per unit weight-on-Earth of propellant) in seconds can be defined by the following equationRocket Propulsion Elements, 7th Edition by George P. Sutton, Oscar Biblarz:

:\mathrm{F_{ m thrust}}=I_{ m sp} \cdot rac{dm} {dt} \cdot g_{ m 0} \,

where:

:Fthrust is the thrust obtained from the engine, in Newton s (or Poundal s).
I

: rac {dm} {dt} is the Mass Flow Rate in kg/s (or lb/s), which is minus the time-rate of change of the vehicle's mass, since fuel is being expelled.
g


(When working with English Unit s, it is conventional to divide both sides of the equation by ''g''0 so that the left hand side of the equation becomes the thrust in Lbf rather than poundals.)

This ''Isp'' in seconds value is somewhat physically meaningful—if an engine's thrust could be adjusted to equal the initial weight of its propellant (measured at one Standard Gravity ), then ''I''sp is the duration the propellant would last. In practice, the specific impulses of real engines vary somewhat with both altitude and thrust; nevertherless, ''I''sp is a useful value to compare engines; much like 'miles per gallon' is used for cars.

The advantage that this formulation has is that it may be used for rockets, where all the reaction mass is carried onboard, as well as aeroplanes, where most of the reaction mass is taken from the atmosphere. In addition, it gives a result that is independent of units used (provided the unit of time used is the second).


ROCKETRY - SPECIFIC IMPULSE IN SECONDS


In rocketry, where the only reaction mass is the propellant, an equivalent way of calculating the specific impulse in seconds is also frequently used. In this sense, specific impulse is defined as the change in momentum per unit Weight -on-Earth of the propellant:

:I_{ m sp}= rac{v_{ m e}}{g_{ m 0}}

where

''I''sp is the specific impulse measured in seconds

v_{ m e} is the average exhaust speed along the axis of the engine in (ft/s or m/s)

''g0'' is the acceleration at the Earth's surface (in ft/s2 or m/s2)

In rockets, due to atmospheric effects, the specific impulse varies with altitude, reaching a maximum in a vacuum. It is therefore most common to see the specific impulse quoted for the vehicle in a vacuum; the lower sea level values are usually indicated in some way (e.g. 'sl').

Interpretations

When expressed in units of seconds, the specific impulse can be interpreted in the following ways:
  • the impulse divided by the sea-level weight of a unit mass of propellant

  • the time one kilogram of propellant lasts if a force equal to the weight of one kilogram is produced, for example a hypothetical vehicle hovering over the Earth (imagine the fuel to be supplied from outside, so that the mass on which the thrust is applied does not reduce by spending fuel)

  • alternatively, for engines that can not produce a large thrust: approximately the time one kilogram of propellant lasts if an acceleration of 0.01 ''g'' of a mass of one 100 kilogram is produced

  • 100 times the time an acceleration ''g'' can be produced (i.e. a thrust equal to the weight on Earth of the current mass) with a propellant mass of 1 % of the current total mass (100 times the time it takes in this case to reduce the total mass by 1 %)

  • the time an acceleration ''g'' can be produced with a propellant mass of 63.2 % of the initial total mass (the time it takes in this case to reduce the total mass by a factor e, to 36.8 %)

  • twice the net power to produce an acceleration of 1 m/s2 to a mass which at Earth has a weight of 1 N (i.e. a mass of 102 grams)


e.g. for hydrogen/oxygen, with a specific impulse of 460 seconds (4500 m/s):
  • one kilogram of propellant lasts 460 seconds if an acceleration ''g'' of a mass of one kilogram is produced

  • one kilogram of propellant lasts 460 seconds if an acceleration of 0.01 ''g'' of a mass of 100 kilogram is produced

  • it takes 4.6 seconds to reduce the total mass by 1 % if an acceleration ''g'' is produced

  • ---an acceleration ''g'' during 460 seconds can be produced with a propellant mass of 63.2 % of the initial total mass (it is the time it takes in this case to reduce the total mass by a factor e, to 36.8 %)

  • the net power to produce an acceleration of 1 m/s2 to a mass of 102 grams is 230 W.


A very simplified example can make this point clear:
Lets look at a hydrogen based engine:

The ideal reaction is: 2H2 + O2 ightarrow2H2O +467 kJ/mol.

If the O2 came from a tank in a rocket the specific gives (again over-simplificated)

: rac{mv^2}{2} =467 \ \mathrm{kJ}, where the mass is 18 g (2H + O, 2 g/mol + 16 g/mol).

Solving for ''v'', we get: 5093 m/s, about 5000 m/s under ideal conditions (ejection temperature 0 K).

If somehow we were to arrange that we wouldn't have to carry the oxygen the mass is now 2 g, and magically the energy was still 467 kJ, we would get: 15,280 m/s.

We can improve that by pushing great amounts of non-combustion air.
This is possible because the energy is proportional to the square of the ejection speed but the “force” is proportional to the speed (due to simple momentum). The presence of nitrogen makes things even better. If we see the diagrams of big, efficient Turbofan s we will see that this is important part of the optimization guides. (http://anirudh.net/seminar/ge90.pdf by example)

So the reason why the specific impulse of a turbofan is so large is partly because the atmosphere provides the oxidant, so the plane does not carry it. But more importantly, the air is used as reaction mass, and the fuel is mainly used as an energy source.


ROCKETRY - SPECIFIC IMPULSE AS A SPEED (EFFECTIVE EXHAUST VELOCITY)


Because of the geocentric factor of ''g''0 in the equation for specific impulse, many prefer to define the specific impulse of a rocket in terms of thrust per unit mass flow of propellant (instead of per unit weight flow). This is an equally valid (and somewhat simpler) way of defining the effectiveness of a rocket propellant. For a rocket, the specific impulse defined in this way is simply the effective exhaust velocity, ve. The two definitions of specific impulse are proportional to one another, and related to each other by:

:v_{ m e} = g_0 I_{ m sp} \,

where

''I''sp is the specific impulse in seconds

''v''e is the specific impulse measured in Metres Per Second (in the U.S. feet/second), which is the same as the effective exhaust velocity measured in metres per second

''g''0 is the Earth's gravitational constant, 9.81 metres per second per second (in English units 32.2 ft/s&2).

(Note that different symbols are sometimes used; for example, ''c'' is also sometimes seen for exhaust velocity. While the symbol ''I''sp might logically be used for specific impulse in units of N·s/kg, to avoid confusion it is desirable to reserve this for specific impulse measured in seconds.)

It is related to the Thrust , or forward force on the rocket by the equation:

:\mathrm{F_{ m thrust}}=v_{ m e} \cdot rac {dm} {dt} \,

where

rac {dm} {dt} is the mass flow rate, which is minus the time-rate of change of the vehicle's mass, since fuel is being expelled.

Interpretations

A rocket must carry all its fuel with it, so the mass of the unburned fuel must be accelerated along with the rocket itself. Minimizing the mass of fuel required to achieve a given push is crucial to building effective rockets. Using Newton's Laws Of Motion it is not difficult to verify that for a fixed mass of fuel, the total change in Velocity (in fact, momentum) it can accomplish can only be increased by increasing the exhaust velocity.

A spacecraft without propulsion follows an orbit determined by the gravitational field. Deviations from the corresponding velocity pattern (these are called Δ''v'' ) are achieved by sending exhaust mass in the direction opposite to that of the desired velocity change.

Due to the law of conservation of momentum, to change the speed of the spacecraft by an amount equal to 1% of the exhaust speed, approximately requires an exhaust mass equal to 1% of the mass of the spacecraft, including the fuel that has not yet been spent.

A useful rule of thumb is that the Δ''v'' that can be produced with a propellant mass of 63.2 % of the initial total mass is equal to the exhaust velocity (see Rocket Equation .)

The speed is also approximately twice the Power per unit thrust

For a Δ''v'' that is much smaller than the specific impulse, the fuel required is approximately proportional to the Δ''v''. For a Δ''v'' that is larger than the specific impulse, this requirement of carrying the fuel and spending much of the fuel on accelerating the fuel, gives rise to an exponential increase in fuel requirement (and larger tanks which also add to the mass).
See Spacecraft Propulsion Calculations and Tsiolkovsky Rocket Equation for details.

e.g for hydrogen/oxygen, with a specific impulse of 4500 m/s (460 seconds):
  • the effective exhaust speed is 4,500 m/s

  • the impulse produced per unit mass of propellant used is 4,500 N·s per kg

  • the Thrust is 4,500 N if the propellant mass flow rate is 1 kg/s

  • the Δ''v'' that can be produced with a propellant mass of 1 % of the current total mass (the Δ''v'' that reduces the mass by 1%) is 45 m/s

  • the Δ''v'' that can be produced with a propellant mass of 63.2 % of the initial total mass (the Δ''v'' that reduces the total mass by a factor e, to 36.8 %) is 4,500 m/s

  • the power-thrust ratio is 2,250 W/N



REFERENCES



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