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FORCE

Assuming the gun and shooter are at rest, the force on the bullet is equal to that on the gun-shooter. This is due to the law of Conservation Of Momentum . Consider a system where the gun and shooter have a combined mass M and the bullet has a mass m. When the gun is fired, the two systems move away from one another with new velocities V and v respectively. But the law of conservation of momentum states that their momenta must be equal:
: MV=mv \qquad (1)

Since force equals the change in momentum and the initial momenta are zero, the force on the bullet must therefore be the same as the force on the gun/shooter.

Hollywood depictions of firearm victims being thrown through plate-glass windows are inaccurate. Were this to be the case, the shooter would also be thrown backwards with equal force. Gunshot victims frequently fall or collapse when shot; this is less a result of the momentum of the bullet pushing them over, but is primarily caused by physical damage or psychological effects, perhaps combined with being off-balance. This is not the case if the victim is hit by heavier projectiles such as 20 mm cannon shell, where the momentum effects can be enormous; this is why very few such weapons can be fired without being mounted on a Weapons Platform or involve a recoilless system e.g. Recoilless Rifle .)


VELOCITY

From Eq. 1 we can write for the velocity of the gun/shooter: V = mv/M. This shows that despite the high velocity of the bullet, the small bullet-mass to shooter-mass ratio results in a low recoil velocity (V) although the force and momentum are equal.


KINETIC ENERGY

However, the smaller mass of the bullet, compared that of the gun-shooter system, allows significantly more Energy to be imparted to the bullet than to the shooter. The Kinetic Energies for the two systems are \begin{matrix} rac{1}{2}\end{matrix}MV^2 for the gun-shooter system and \begin{matrix} rac{1}{2}\end{matrix}mv^2 for the bullet. The energy imparted to the shooter can then be written as:
: rac{1}{2}MV^2= rac{1}{2}M\left( rac{mv}{M} ight)^2= rac{m}{M} rac{1}{2}mv^2

If we now write for the ratio of the energies we have:
: rac{ rac{1}{2}MV^2}{ rac{1}{2}mv^2} = rac{m}{M} \qquad (2)

The ratio of the energies is the same as the ratio of the masses (and is independent of velocity). Since the mass of the bullet is much less than that of the shooter there is more kinetic energy transferred to the bullet than to the shooter. The larger kinetic energy of the bullet is then dissipated in the target.


TRANSFER OF ENERGY

When the bullet strikes, its high velocity and small area means that it will exert large Stress es in any object it hits. This usually results in it penetrating any soft object, such as flesh. The energy is then dissipated in the wound tract formed by the passage of the bullet. See Terminal Ballistics for a fuller discussion of these effects.

Bulletproof Vest s work by dissipating the bullet's energy in another way; the vest's material, usually Kevlar , works by presenting a series of material layers which catch the bullet and spread its imparted force over a larger area, hopefully bringing the round to a stop before it can penetrate into the body. While the vest can prevent a bullet from penetrating, the wearer will still be affected by the kinetic energy of the bullet, which can produce serious internal injuries.


OTHER INFORMATION

The television show '' that the lower velocity weapons would still provide lethal penetration at a distance of 8-10 feet, while the projectiles from the higher velocity weapons would fragment upon contact with the water.

They followed this with , using a Beretta 9mm automatic pistol, a .357 magnum, a Garand M1, and a shotgun. While all the guns successfully fired underwater, the shotgun was completely destroyed, with the barrel splitting. The bullets were able to provide lethal penetration after traveling no more than two feet.


SEE ALSO