Parallelepiped


	align	center colspan=2
	bgcolor	#e7dcc3Type Prism
	bgcolor	#e7dcc3Faces6 Parallelogram s
	bgcolor	#e7dcc3Edges12
	bgcolor	#e7dcc3Vertices8
	bgcolor	#e7dcc3 Symmetry Group ''C''<sub>''i''</sub>
	bgcolor	#e7dcc3Propertiesconvex

	This Is True Because The ''base'' Parallelogram Has Two Edges As The Vectors '''b''' And '''c''', Which Have An Internal Angle Of ''&theta'' The Area Of This Parallelogram Is '''b''''''c'''sin''&theta''	'''b''' &times '''c''' The reason for this is that a parallelogram can be considered as two similar triangles - one of them having edges '''b''' and '''c''' which means the area of one of these triangles is ½'''b''''''c'''sin''&theta'' (formula for area of a triangle)
	From The Diagram, The Height Is Perpendicular To '''b''' And Equal To '''a'''cos''&alpha'' Where ''&alpha'' Is The Angle Between '''a''' And ('''b''' &times '''c''') So Base &times Height	'''b''' &times '''c''' &times '''a'''cos''&alpha'', which is the scalar product of '''a''' and ('''b''' &times '''c''')

	CATEGORIES ABOUT PARALLELEPIPED

	prismatoid polyhedra

	zonohedra

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