Information About

Gyroradius





DERIVATION

If the charged particle is moving, then it will experience a Lorentz Force given by:

: ec{F} = q( ec{v} imes ec{B})

Where ec{v} is the velocity vector, ec{B} is the magnetic field vector, and q is the particle's Electric Charge . Notice that the direction of the force is given by the Cross Product of the velocity and magnetic field. Thus, the Lorentz force will always act perpendicular to the direction of motion, causing the particle to move in a circle ( Gyrate ). The radius of this circle r_g can be determined by equating the magnitude of the Lorentz force to the Centripetal Force :

: rac{m v^2}{r_g} = qvB

Here m is the particle Mass . Solving for r_g, the gyroradius is determined to be:

:r_g = rac{m v}{q B}

Thus, the gyroradius is directly proportional to the particle mass and velocity, and inversely proportional to the particle electric charge, and the magnetic field.

Similarly, the Frequency of this circular motion is known as the gyrofrequency, and is given by:

:
u = rac{q B}{2 \pi m}


SEE ALSO



REFERENCES & FURTHER READING


# 1