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Birch-murnaghan Equation Of State




:
E = E_0 + rac{1}{2} B_0 rac{(V-V_0)^2}{V_0}.


The next simplest reasonable model would be with a constant bulk modulus
:
B = - V \left( rac{\partial P}{\partial V} ight)_T. (2)


:
E = E_0 + B_0 \left( V_0 - V + V \ln(V/V_0) ight).



MURNAGHAN EQUATION OF STATE


A more sophisticated equation of state was derived by
F. D. Murnaghan of Johns Hopkins University in 1944. To begin with, we consider the pressure
: P = - \left( rac{\partial E}{\partial V} ight)_S (1)

and the bulk modulus
:
B = - V \left( rac{\partial P}{\partial V} ight)_T. (2)

Experimentally, the bulk modulus pressure derivative
:
B' = \left( rac{\partial B}{\partial P} ight)_T (3)

is found to change little with pressure. If
we take B' = B'_0 to be a constant, then
:
B = B_0 + B'_0 P (4)

where B_0 is the value of B when P = 0.
We may equate this with (2) and rearrange as
:
rac{d V}{V} = - rac{d P}{B_0 + B'_0 P}. (5)

Integrating this results in
:
P(V) = rac{B_0}{B'_0} \left(\left( rac{V_0}{V} ight)^{B'_0}
- 1 ight) (6)

or equivalently
:
V(P) = V_0 \left(1+B'_0
rac{P}{B_0} ight)^{-1/B'_0}. (7)

Substituting (6) into E = E_0 - \int P
dV then results in the equation of state
for energy.
:
E(V) = E_0
+ rac{ B_0 V }{ B_0' } \left( rac{ (V_0/V)^{B_0'} }{ B_0' - 1 } + 1 ight)
- rac{ B_0 V_0 }{ B_0' - 1 }. (8)


Many substances have a fairly constant B'_0 of about 3.5.


BIRCH-MURNAGHAN EQUATION OF STATE


The third-order Birch-Murnaghan isothermal equation of state, published in 1947 by Francis Birch of Harvard , is given by:

:
P(V)= rac{3B_0}{2}
\left[\left( rac{V_0}{V} ight)^ rac{7}{3} -
\left( rac{V_0}{V} ight)^ rac{5}{3} ight]
\left\{1+ rac{3}{4}\left(B_0^\prime-4 ight)
\left[\left( rac{V_0}{V} ight)^ rac{2}{3} - 1 ight] ight\}


Again, E(V) is found by integration of the pressure:
:
E(V) = E_0 + rac{9V_0B_0}{16}
\left\{
\left[\left( rac{V_0}{V} ight)^ rac{2}{3}-1 ight]^3B_0^\prime +
\left[\left( rac{V_0}{V} ight)^ rac{2}{3}-1 ight]^2
\left[6-4\left( rac{V_0}{V} ight)^ rac{2}{3} ight] ight\}



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