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Dyson Operator





THE DYSON OPERATOR


We suppose we have a Hamiltonian H which for some reason or other, we split into a "free" part ''H0'' and an "interacting" part ''V'' i.e. ''H=H0+V''. We will work in the Interaction Picture here.

In the Interaction Picture , the ''evolution operator U'' defined by the equation:

:
\Psi(t)=U(t,t_0)\Psi(t_0)


is called Dyson operator.

We have

:
U(t,t)=I,\ U(t,t_0)=U(t,t_1)U(t_1,t_0),\ U^{-1}(t,t_0)=U(t_0,t)


and then ( Tomonaga-Schwinger Equation )

:
i{d \over dt} U(t,t_0)\Psi(t_0) = V(t) U(t,t_0)\Psi(t_0)


Thus:

:U(t,t_0)=1 - i \int_{t_0}^t{dt_1\ V(t_1)U(t_1,t_0)}


DERIVATION OF THE DYSON SERIES


This leads to the following Neumann Series :
:U(t,t_0)=1 - i \int_{t_0}^t{dt_1V(t_1)}+(-i)^2\int_{t_0}^t{dt_1\int_{t_0}^{t_1}{dt_2V(t_1)V(t_2)}}+...+(-i)^n\int_{t_0}^t{dt_1\int_{t_0}^{t_1}{dt_2...\int_{t_0}^{t_{n-1}}{dt_nV(t_1)V(t_2)...V(t_n)}}}

If we assume that t>t_1>t_2>...>t_n we can say that the fields are Time Ordered , and so it is useful to introduce an operator called '' Time-ordering operator''. Defining:

:U_n(t,t_0)=(-i)^n\int_{t_0}^t{dt_1\int_{t_0}^{t_1}{dt_2...\int_{t_0}^{t_{n-1}}{dt_n\mathcal TV(t_1)V(t_2)...V(t_n)}}}

We can now try to make this integration simpler. in fact, in the following example:
:S_n=\int_{t_0}^t{dt_1\int_{t_0}^{t_1}{dt_2...\int_{t_0}^{t_{n-1}}{dt_nK(t_1, t_2,...,t_n)}}}

If K is symmetric in its arguments, we can define (look at integration limits):

:K_n=\int_{t_0}^t{dt_1\int_{t_0}^t{dt_2...\int_{t_0}^t{dt_nK(t_1, t_2,...,t_n)}}}

And so it is true that:

:S_n= rac{1}{n!}K_n

Returning to our previous integral, it holds the identity:

:U_n= rac{(-i)^n}{n!}\int_{t_0}^t{dt_1\int_{t_0}^t{dt_2...\int_{t_0}^t{dt_n\mathcal TV(t_1)V(t_2)...V(t_n)}}}

Summing up all the terms we obtain the Dyson series:

:U(t,t_0)=\sum_{n=0}^\infty U_n(t,t_0)=\mathcal Te^{-i\int_{t_0}^t{d au V( au)}}


THE DYSON SERIES FOR WAVEFUNCTIONS


Then, going back to the wavefunction for t>t0,

  :<math>\langle\psi Ft F\psi It I Angle \sum_{n=0}^\infty (-i)^n\begin{matrix}\underbrace{\int dt_1 \cdots dt_n}\t_f\ge t_1\ge \dots\ge t_n\ge t_i\end{matrix}\langle\psi_ft_fe^{-iH_0(t_f-t_1)}Ve^{-iH_0(t_1-t_2)}\cdots Ve^{-iH_0(t_n-t_i)}\psi_it_i angle</math>